12/23/2023 0 Comments Webpage url extractor![]() There are some websites that load most of their content using JavaScript. However, I highly encourage you not to do that that will cause a lot of requests and will crowd the web server, and may block your IP address.Īfter the crawling finishes, it'll print the total links extracted and crawled: Total Internal links: 90Īwesome, right? I hope this tutorial was a benefit for you to inspire you to build such tools using Python. Get -35 OFF: Ethical Hacking with Python EBook Print(" Total URLs:", len(external_urls) + len(internal_urls)) Print(" Total External links:", len(external_urls)) Print(" Total Internal links:", len(internal_urls)) Otherwise, I'm not responsible for any harm you cause. As a result, I've added a max_urls parameter to exit when we reach a certain number of URLs checked.Īlright, let's test this make sure you use this on a website you're authorized to. However, this can cause some issues the program will get stuck on large websites (that got many links) such as. This function crawls the website, which means it gets all the links of the first page and then calls itself recursively to follow all the links extracted previously. Let's finish up the function: if not is_valid(href): Href = parsed_href.scheme + "://" + parsed_loc + parsed_href.path # remove URL GET parameters, URL fragments, etc. Now we need to remove HTTP GET parameters from the URLs, since this will cause redundancy in the set, the below code handles that: parsed_href = urlparse(href) Since not all links are absolute, we gonna need to join relative URLs with their domain name (e.g when href is "/search" and url is "", the result will be "/search"): # join the URL if it's relative (not absolute link) Otherwise, we just continue to the next link. ![]() So we get the href attribute and check if there is something there. Let's get all HTML a tags (anchor tags that contains all the links of the web page): for a_tag in soup.findAll("a"): Third, I've downloaded the HTML content of the web page and wrapped it with a soup object to ease HTML parsing. We gonna need it to check whether the link we grabbed is external or internal. Second, I've extracted the domain name from the URL. Soup = BeautifulSoup(requests.get(url).content, "html.parser")įirst, I initialized the urls set variable I've used Python sets here because we don't want redundant links. # domain name of the URL without the protocol Returns all URLs that is found on `url` in which it belongs to the same website Now let's build a function to return all the valid URLs of a web page: def get_all_website_links(url): This will ensure that a proper scheme (protocol, e.g http or https) and domain name exist in the URL. Since not all links in anchor tags ( a tags) are valid (I've experimented with this), some are links to parts of the website, and some are javascript, so let's write a function to validate URLs: def is_valid(url):
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